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# (Solved): The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of a ...

The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of an ideal gas are related by the equatic PV = 8.317. Find the rate at which the pressure is changing when the temperature is 400 K and increasing at a rate of 0.1 K/s and the volume is 100 L and increasing at a rate of 0.2 L/s. Solution If t represents the time elapsed in seconds, then at the given instant, we have T = 400, P = 8.31 the chain rule gives the following. (Round your final answer to five decimal places.) dp aP dT aP dv dt + at dt av dt 11 8.31 dT V dt 8.31 100 dv dt 8.31(400) 100² dT = 0.1, V = 100, dv dt dt The pressure is decreasing at a rate (in kPA/s), rounded to three decimal places, of about KPA/s. = 0.2. Since

The pressure (in kilopascals), volume (in liters), and temperature (in kelvins) of a mole of an ideal gas are related by the equat . Find the rate at which the pressure is changing when the temperature is and increasing at a rate of and th volume is and increasing at a rate of . Solution If represents the time elapsed in seconds, then at the given instant, we have ince the chain rule gives the following. (Round your final answer to five dedimal places.) The pressure is decreasing at a rate (in kPA/s), rounded to three decimal places, of about .

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