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The figure shows a plot of potential energy $U$ versus position $x$ of a $0.280kg$ particle that can travel only along an $x$ axis under the influence of a conservative force. The graph has these values: $U_{4}=9.00J,U_{C}=20.0J$ and $U_{0}=24.0J$. The particle is released at the point where $U$ forms a "potential hill" of "height" $U_{B}=120$ ), with kinetic energy $3.50J$. What is the speed of the particle at (a)k $=3.50m$ and (b) $x=6.50m$ ? What is the position of the turning point on (c) the right side and (d) the left side?

To solve this problem, we need to analyze the potential energy graph and make use of the conservatio...

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