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in discrete math please and thank you.

Suppose you wish to use mathematical induction to prove that: $1?1!+2?2!+3?3!+?+n?n!=(n+1)!?1$ for all $n?1$ What is $P(k+1)$ ? $1?1!+2?2!+?+(k+1)(k+1)!=(k+1)!?11?1!+2?2!+?+(k+1)(k+1)!=(k+2)!?11?1!+2?2!+?+k?k!=(k+1)!?11?1!+2?2!+?+(k+1)!?1=(k+1)!(k+2)?1?$

To prove the equation using mathematical induction, we need to show that it holds for the base case (n = 1) and then assume it holds for some arbitrar

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