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Consider the following truth table: In this table, a 1 or 0 indicates an output which must be set, given the inputs $A,B$, and $C$. Write boolean expressions for Q1.1, Q1.2, Q1.3, Q1.4 in terms of A, B, C. Partial credit will be awarded for answers not in simplest terms; for full credit, you must submit the simplest possible answer (i.e. the answer which requires the fewest operations). Note: The answer checker will only accept answers which are sequences of "A", "B", "C", "1", "0", and characters among "()*+!". Use ! for NOT, * for AND, + for OR, and () for grouping and precedence. Spaces are allowed, but will be ignored. An example answer looks like this: $(!A∗!B)+(!C+!D)$ This question will be scored as follows: First, your solution is compared against the reference solution on all valid inputs. If there is a mismatch, the solution is scored as 0 . Otherwise, your score is computed as $(r+1)/(s+1)$, where $r$ is the number of boolean operators in our reference solution, and $s$ is the number of boolean operators in the student submission. It is possible to get more than $100%$ on this question if your solution uses less boolean operators than the staff solution.

Given Truth table is,

Using k-map we write the boolean expressions for Q1.1, Q1.2, Q1.3 and Q1.4

To fi...

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